An ordinary bloke puts $10, on one hand of blackjack. Not only did he win, he got blackjack, which generally pays a bonus on top of the win. level 2.

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Once you split your two cards into two hands, you'll place your original bet with one hand and place an equal bet on the second, split hand. You will play the.

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The Pros and Cons of Playing Multiple Hands in the Same Blackjack Game. For some players at a blackjack table, playing just one hand might not be enough.

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After seeing their hand, a player can Double by placing an additional bet equal to their original bet and subsequently drawing one and only one additional card.

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An ordinary bloke puts $10, on one hand of blackjack. Not only did he win, he got blackjack, which generally pays a bonus on top of the win. level 2.

Enjoy!

It may add to the house edge long term, but short term, it doesn't change your odds of winning. I'm going to guess that $ is a lot to that man.

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Once all bets have been placed, each player and the dealer are given two cards. In a single-deck game dealt from the hand, cards are dealt facedown and you.

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Software - MORE

Once you split your two cards into two hands, you'll place your original bet with one hand and place an equal bet on the second, split hand. You will play the.

Enjoy!

Software - MORE

The Pros and Cons of Playing Multiple Hands in the Same Blackjack Game. For some players at a blackjack table, playing just one hand might not be enough.

Enjoy!

An ordinary bloke puts $10, on one hand of blackjack. Not only did he win, he got blackjack, which generally pays a bonus on top of the win. level 2.

Enjoy!

Thanks for the kind words. There are cards remaining in the two decks and 32 are tens. Unless you are counting cards you have the free will to bet as much as you want. I know, I know, its some sort of divine intervention betting system I am talking about and no betting system affects the house edge. So standing is the marginally better play. Or does it mean that on any given loss it is a 1 in chance that it was the first of 8 losses coming my way? Determine the probability that the player will resplit to 3 hands. Multiply dot product from step 7 by probability in step 5. Here is how I did it. Steve from Phoenix, AZ. Determine the probability that the player will resplit to 4 hands. Resplitting up to four hands is allowed. Besides every once in awhile throwing down a bigger bet just adds to the excitement and for some reason it seems logical that if you have lost a string of hands you are "due" for a win. These expected values consider all the numerous ways the hand can play out. For each rank determine the probability of that rank, given that the probability of another 8 is zero. Thanks for your kind words. Probability of Blackjack Decks Probability 1 4. So, the best card for the player is the ace and the best for the dealer is the 5. The best play for a billion hands is the best play for one hand. Multiply this dot product by the probability from step 2. From my section on the house edge we find the standard deviation in blackjack to be 1. It may also be the result of progressive betting or mistakes in strategy. If I'm playing for fun then I leave the table when I'm not having fun any longer. Expected Values for 3-card 16 Vs. Repeat step 3 but multiply by 3 instead of 2. If there were a shuffle between hands the probability would increase substantially. The probability of this is 1 in 5,,, For the probability for any number of throws from 1 to , please see my craps survival tables. From my blackjack appendix 7 we see that each 9 removed from a single deck game increases the house edge by 0. It took me years to get the splitting pairs correct myself. Blackjack is not entirely a game of independent trials like roulette, but the deck is not predisposed to run in streaks. I would have to do a computer simulation to consider all the other combinations. According to my blackjack appendix 4 , the probability of an overall win in blackjack is I'm going to assume you wish to ignore ties for purposes of the streak. If you were to add a card as the dealer you should add a 5, which increases the house edge by 0. Let n be the number of decks. It is more a matter of degree, the more you play the more your results will approach the house edge. If you want to deviate from the basic strategy here are some borderline plays: 12 against 3, 12 against 4, 13 against 2, 16 against Deviating on these hands will cost you much less. What is important is that you play your cards right. I have a very ugly subroutine full of long formulas I determine using probability trees.{/INSERTKEYS}{/PARAGRAPH} Take another 8 out of the deck. You ask a good question for which there is no firm answer. If the probability of a blackjack is p then the probability of not getting any blackjacks in 10 hands is 1- 1-p For example in a six deck game the answer would be 1- 0. Putting aside some minor effects of deck composition, the dealer who pulled a 5 to a 16 the last five times in a row would be just as likely to do it the next time as the dealer who had been busting on 16 for several hours. To test the most likely case to favor hitting, 8 decks and only 3 cards, I ran every possible situation through my combinatorial program. What you have experienced is likely the result of some very bad losing streaks. Is it that when I sit down at the table, 1 out of my next playing sessions I can expect to have an 8 hand losing streak? This is not even a marginal play. Since this question was submitted, a player held the dice for rolls on May 23, in Atlantic City. According to my blackjack appendix 9H the expected return of standing is So my hitting you will save 6. There is no sound bite answer to explain why you should hit. {PARAGRAPH}{INSERTKEYS}This is a typical question one might encounter in an introductory statistics class. Streaks, such as the dealer drawing a 5 to a 16, are inevitable but not predictable. Your question however could be rephrased as, "what is the value of the ace, given that the other card is not a ten. I hope this answers your question. Repeat step 3 but multiply by 4 instead of 2, and this time consider getting an 8 as a third card, corresponding to the situation where the player is forced to stop resplitting. The fewer the decks and the greater the number of cards the more this is true. Because the sum of a large number of random variables always will approach a bell curve we can use the central limit theorem to get at the answer. I recently replaced my blackjack appendix 4 with some information about the standard deviation which may help. Take the dot product of the probability and expected value over each rank. When I said the probability of losing 8 hands in a row is 1 in I meant that starting with the next hand the probability of losing 8 in a row is 1 in The chances of 8 losses in a row over a session are greater the longer the session. Determine the probability that the player will not get a third eight on either hand. It would take about 5 years playing blackjack 40 hours a week before this piece of advice saved the player one unit. In general the variation in the mean is inversely proportional to the square root of the number of hands you play. It depends on the number of decks. For how to solve the problem yourself, see my MathProblems. You are forgetting that there are two possible orders, either the ace or the ten can be first. The following table displays the results. In that case, the probability of a win, given a resolved bet, is The probability of winning n hands is a row is 0. Add values from steps 4, 8, and The hardest part of all this is step 3. Following this rule will result in an extra unit once every hands. Any basic statistics book should have a standard normal table which will give the Z statistic of 0. The standard deviation of one hand is 1. There are 24 sevens in the shoe. All of this assumes flat betting, otherwise the math really gets messy. As I always say all betting systems are equally worthless so flying by the seat of your pants is just as good as flat betting over the long term. Multiply dot product from step 11 by probability in step 9. However if you were going to cheat it would be much better to remove an ace, which increases the house edge by 0. That column seemed to put the mathematics to that "feeling" a player can get. When the dealer stands on a soft 17, the dealer will bust about When the dealer hits on a soft 17, the dealer will bust about According to my blackjack appendix 4 , the probability of a net win is However, if we skip ties, the probability is So, the probability of a four wins in a row is 0. I have no problem with increasing your bet when you get a lucky feeling. For the non-card counter it may be assumed that the odds are the same in each new round. However there are other ways you get four aces in the same hand, for example the last card might be an 8 or 9. Here is the exact answer for various numbers of decks. It depends whether there is a shuffle between the blackjacks. Cindy of Gambling Tools was very helpful. My question though is what does that really mean? So the probability of winning six in a row is 0. Go through all ranks, except 8, subtract that card from the deck, play out a hand with that card and an 8, determine the expected value, and multiply by 2.